wt/vol

 

wt/vol

MW

moles

density

equivs.

yield

I

3.157 g

218.37

0.0145

 

1.0

 

II

40 mL

-

-

 

 

 

III

0.050 g

24.0

0.0021

 

 

 

IV

2.901 g

260.45

0.0111

 

 

(77%)

 

Procedure:  250 mL 1-neck flask, stirbar, septum, N2 inlet

                  Dissolved 3.157 g of lactate I in 40 mL of neat isobutanol.  Stirred at rt.  Added 0.050 g of NaH (60% disp. in mineral oil).  After 16 h, TLC shows product spot at Rf 0.70 (1:9 EtOAc-hexanes, I2).  The reaction mixture was poured into 1.0 M HCl and extracted with EtOAc.  The organic layer was dried over MgSO4, filtered and the solvent was removed by rotary evaporation.  The product was isolated by flash chromatography on silica gel using 1:19 EtOAc-hexanes as eluant.  The product was a clear, colorless oil.

 

1H NMR (CDCl3, 300 MHz) d 4.32 (q, J = 6.7 Hz, H2, 1H), 3.90 (m, 2H, CO2CH2), 1.95 (septet, J = 6.6 Hz, CH(CH3)2, 1H), 1.40 (d, J = 6.6 Hz, H3, 3H), 0.93 (d, J = 6.6 Hz, CH(CH3)2, 6H), 0.90 (s, Si(CH3)3, 9H), 0.09 (s, Si(CH3)2, 3H), 0.06 (s, Si(CH3)2, 3H). 

 

notes

 

This reaction is actually catalytic in NaH.  The initial addition of sodium hydride forms the alkoxide of isobutanol.  The isobutoxide then displaces methoxide to give the desired ester and NaOMe.  NaOMe is basic enough to react with additional isobutanol to generate more isobutoxide and drive the whole process.